题解 | #牛牛的水杯#
牛牛的水杯
https://www.nowcoder.com/practice/c196c47c23394bf3bdd4f82a838df6bf
#include<stdio.h> //
#define PI 3.14
int main() {
int h, r;
scanf("%d %d", &h, &r);
double v = PI * h * r * r * 0.001;
double n = (int)(10.0 / v); //这儿需要把浮点型强转换为int型,二者去作比较,相同则为满杯;不相等则会多出来
if(n == (10.0 / v))
printf("%d", (int)n);
else
printf("%d", (int)(n + 1));
return 0;
}
#define PI 3.14
int main() {
int h, r;
scanf("%d %d", &h, &r);
double v = PI * h * r * r * 0.001;
double n = (int)(10.0 / v); //这儿需要把浮点型强转换为int型,二者去作比较,相同则为满杯;不相等则会多出来
if(n == (10.0 / v))
printf("%d", (int)n);
else
printf("%d", (int)(n + 1));
return 0;
}