题解 | #矩阵相等判定#二维数组解法
矩阵相等判定
http://www.nowcoder.com/practice/2f058b1e89ae43f7ab650c0fd0b71fa8
so easy 一把过
row,col = map(int,input().split())
a= [[0 for _ in range(0,row+10)]for _ in range(0,col+10) ]
b=[[0 for _ in range(0,row+10)]for _ in range(0,col+10) ]
for i in range(0,row):
a[i]=list(map(int,input().split()))
for i in range(0,row):
b[i]=list(map(int,input().split()))
flag = 0
for i in range(0,row):
for j in range(0,col):
if (a[i][j]!=b[i][j]):
flag=-1
break
if flag == 0:
print("Yes")
else:
print("No")
左边刷题右边 chat 效果很好