有做了网易游戏研发工程师第三批笔试的吗？

同只做出来两题，第三题用了普通的，走过不能重复走的，深搜，测试样例过了，但是提交了就是超时0%，这要是走过可以重复走，时间就更爆炸了，哪个大佬来给点提示第三题怎么做。

老哥收到面试了吗  我下周一

2题，下周二面试，我本来投的后台服务器开发，然后hr打电话问我愿意转游戏开发吗，哈哈，直接帮我改的意向

各位3题做了两题的笔试过了吗，我已经凉了😂最后一批要求这么高吗，还是人已经招满了

//有没有大佬帮看看第二题呢，只过了测试样例，提交0%，呜呜呜呜呜~~~ #include <iostream> #include <cstdio> #include<string> using namespace std; int process(string s) { int count = 0; bool flag = false; for (int i = 0; i < s.size(); i++) { if (s[i] == ')') flag = false; if (s[i] == '(') flag = true; if (flag==false&&(s[i] >= 'a'&&s[i] <= 'z') || (s[i] >= 'A'&&s[i] <= 'Z')) { count++; } } return count; } int main() { int T; cin >> T; for (int i = 0; i < T; i++) { int N; cin >> N; int count = 0; string s; char c = getchar(); for (int j = 0; j < N; j++) { getline(cin, s); count+=process(s); if (s[0] == '+') count++; } cout << count<<endl; } return 0; }

//第二题测试用例过，提交通过 0%。有没有大佬帮看一下问题在哪里？谢过！ #include <iostream> #include <cstdio> #include<string> using namespace std; int process(string s) {     int count = 0;     bool flag = false;     for (int i = 0; i < s.size(); i++) {         if (s[i] == ')')             flag = false;         if (s[i] == '(')             flag = true;         if (flag==false&&(s[i] >= 'a'&&s[i] <= 'z') || (s[i] >= 'A'&&s[i] <= 'Z')) {             count++;         }     }     return count; } int main() {     int T;     cin >> T;     for (int i = 0; i < T; i++) {         int N;         cin >> N;         int count = 0;         string s;         char c = getchar();         for (int j = 0; j < N; j++) {             getline(cin, s);             count+=process(s);             if (s[0] == '+')                 count++;         }         cout << count<<endl;     }     return 0; }

// 代码分享 // 第一题 100% #include <iostream> using namespace std; static int dirs[4][2] = { {-1, -1}, {-1, 1}, {1, 1}, {1, -1} }; int solve(int n, int m, int x, int y, int dx, int dy, int t) { int res = 0; for (int i = 0; i < t; ++i) { x += dx; y += dy; if (x == 2 || x == n - 1) { ++res; dx = -dx; } if (y == 2 || y == m - 1) { ++res; dy = -dy; } } return res; } int main() { int Q = 0; cin >> Q; while (Q--) { int N = 0, M = 0; cin >> N >> M; int X = 0, Y = 0, W = 0, T = 0; cin >> X >> Y >> W >> T; int res = solve(N, M, X, Y, dirs[W][0], dirs[W][1], T); cout << res << endl; } return 0; } // 第二题 100% #include <iostream> #include <string> #include <vector> using namespace std; int solve(string str) { int res = 0; switch(str[0]){ case '#': res = solve(str.substr(1)); break; case '+': res = solve(str.substr(2)) + 1; break; default: int n = str.size(); bool flag = false; for (int i = 0; i < n; ++i) { if (str[i] == '(') { if (i > 0 && str[i - 1] == ']') { flag = true; res -= 2; } else { ++res; } } else if (str[i] == ')'){ if (flag) { flag = false; } else { ++res; } } else{ if (!flag) { ++res; } } } break; } return res; } int main() { int T = 0; cin >> T; while (T--) { int N = 0; cin >> N; getchar(); vector<string> content(N); for (int i = 0; i < N; ++i) { getline(cin, content[i]); } int res = 0; for (int i = 0; i < N; ++i) { cout << content[i] << endl; res += solve(content[i]); } cout << res << endl; } return 0; } // 第三题 0% 超时 深搜 #include <iostream> #include <string> #include <vector> #include <algorithm> #include <cctype> #include <climits> using namespace std; // 左 右 下 上 static int dirs[4][2] = { {0, -1}, {0, 1}, {1, 0}, {-1, 0} }; void dfs(vector<string> & matrix, vector<int> &weight, vector<vector<int>> &visited, int x, int y, int tx, int ty, int di, int qian, int you, int path, int &res){ int m = matrix.size(), n = matrix[0].size(); if (x == tx && y == ty) { path += weight[di]; res = min(path, res); return; } visited[x][y] = 1; for (int d = 0; d < 4; ++d) { int newx = x + dirs[d][0]; int newy = y + dirs[d][1]; int newd = di, newq = qian, newyou = you; if (newx >= 0 && newx < m && newy >= 0 && newy < n && !visited[newx][newy] && matrix[newx][newy] == '.') { switch (d) { case 0: newd = 5 - you; newyou = di; break; case 1: newd = you; newyou = 5 - di; break; case 2: newd = qian; newq = 5 - di; break; case 3: newd = 5 - qian; newq = di; break; } dfs(matrix, weight, visited, newx, newy, tx, ty, newd, newq, newyou, path + weight[di], res); } } visited[x][y] = 0; } int main() { int T = 0; cin >> T; while (T--) { int M = 0, N = 0; cin >> M >> N; vector<string> matrix(M); for (int i = 0; i < M; ++i) { cin >> matrix[i]; } int sx, sy, tx, ty; cin >> sx >> sy >> tx >> ty; vector<int> weight(6); for (int i = 0; i < 6; ++i) { cin >> weight[i]; } if (matrix[sx][sy] == '#' || matrix[tx][ty] == '#') { cout << -1 << endl; } else { int res = 0x3f3f3f3f; vector<vector<int>> visited(M, vector<int>(N, 0)); dfs(matrix, weight, visited, sx, sy, tx, ty, 4, 0, 2, 0, res); cout << (res == 0x3f3f3f3f ? -1 : res) << endl; } } return 0; }

就做了一个 是不是凉凉

帮别人做了1和3，不过3写了一个小时，发给他后他没时间交，晕 感觉第三题就是记录一下状态（每个位置都要24维表示魔方状态）然后搜索就行了？  

菜鸡看着前面的大佬瑟瑟发抖。。死磕第二题加号那个情况一直过不去。。直接凉

写题一小时 改输入一个半小时🙃

同问第二题，本地IDE可以过，在线提交tab键有问题

求问一下第二题的输入怎么解决的？我用getline为什么最后一行读不进去

同两题，第三题感觉还需要更多时间，但也许就是做不出来