#include <iostream>
#include <vector>
#include <numeric>
#include <limits>
using namespace std;
/** 请完成下面这个函数,实现题目要求的功能 **/
/** 当然,你也可以不按照这个模板来作答,完全按照自己的想法来 ^-^ **/
int findCircleNum(vector < vector < int > > M) {
int n = M.size();
if (n == 0)
return 0;
vector<int> dp(n + 1);
dp[0] = 0; dp[1] = 1;
for (int i = 2; i <= n; i++){
dp[i] = dp[i - 1] + 1;
for (int j = 0; j < i - 1; j++){
if (M[i - 1][j] == 1){
dp[i] = dp[i - 1];
break;
}
}
}
return dp[n-1];
}
int main() {
int res;
int _M_rows = 0;
int _M_cols = 0;
cin >> _M_rows >> _M_cols;
vector< vector < int > > _M(_M_rows);
for (int _M_i = 0; _M_i<_M_rows; _M_i++) {
for (int _M_j = 0; _M_j<_M_cols; _M_j++) {
int _M_tmp;
cin >> _M_tmp;
_M[_M_i].push_back(_M_tmp);
}
}
res = findCircleNum(_M);
cout << res << endl;
system("pause");
return 0;
}
求解?为什么return dp[n-1] AC了,但是return dp[n]通过率为0%,感觉return dp[n]才是正解呀