n皇后
https://ac.nowcoder.com/acm/contest/17106/K
#include <bits/stdc++.h> using namespace std; const int N = 1e5+10; long long res[N]; const int M = 1e9+7; int main() { int n,t; res[1] = 1; for(int i=2;i<=N-10;i++) res[i]=res[i-1]*i%M; cin>>t; while(t--) { cin>>n; printf("%lld\n",res[n]); } return 0; }
每天在博客写一些题解，为了思路更加清晰。
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const flattern = (obj) => {
const res = {};
const dfs = (curr, path) => {
if(typeof curr === 'object' && curr !== null) {
const isArray = Array.isArray(curr);
for(let key in curr) {
const newPath = path ? isArray ? `${path}[${key}]` : `${path}.${key}` : key;
dfs(curr[key], newPath);
}
} else {
res[path] = curr
}
}
dfs(obj);
return res;
}
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