题解 | #整数与IP地址间的转换#
整数与IP地址间的转换
http://www.nowcoder.com/practice/66ca0e28f90c42a196afd78cc9c496ea
想得有点复杂了
def ip_change(string,i):
if i == 0:
# 将ip转化成普通数组
string = string.split('.')
a = []
for i in string:
# ip 一位数字二进制的最大长度是8，不足则用‘0’补齐
a.append('0'*(8-len(bin(int(i))[2:]))+bin(int(i))[2:])
b = int(''.join(i for i in a),2)
return b
if i == 1:
bin1 = str(bin(int(string))[2:])
a = []
b = []
# 密码二进制默认32位，遍历时可以将其补齐 32 位
for i in range(len('0'*(32-len(bin1))+bin1)//8):
a.append(bin1[::-1][i*8:(i+1)*8][::-1])
a = a[::-1]
for i in a :
b.append(int(i,2))
return '.'.join(str(i) for i in b )
for i in range(2):
string = input().strip()
print(ip_change(string,i))
