题解 | #数组元素反转#

#include <iostream>
using namespace std;

int main() {

    int arr[6] = { 0 };

    int len = sizeof(arr) / sizeof(int);
    
    for (int i = 0; i < len; i++) {
        cin >> arr[i];
    }

    cout << "[";
    for (int i = 0; i < len; i++) {
        if (i == len - 1) {
            cout << arr[i] << "]" << endl;
            break;
        }
        cout << arr[i] << ", ";
    }

    //方法一:使用一个辅助数组来进行更换
//     int copy_arr[6] = { 0 };
//     for(int i =len-1;i>=0;i--)
//     {
//         copy_arr[len-i-1]=arr[i];
//     }
    
    
    //方法二：使用双指针进行替换
    int temp;
    //指向首尾的双指针
    int left = 0;
    int right = 5;
    while(left<right)
    {
        //对首尾的指针进行移动
        temp = arr[left];
        arr[left] = arr[right];
        arr[right] = temp;
        left++;
        right--;
    }

    cout << "[";
    for (int i = 0; i < len; i++) {
        if (i == len - 1) {
            cout << arr[i] << "]" << endl;
            break;
        }
        cout << arr[i] << ", ";
    }

    return 0;
}