题解 | #把数字翻译成字符串#
把数字翻译成字符串
http://www.nowcoder.com/practice/046a55e6cd274cffb88fc32dba695668
#
# 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
#
# 解码
# @param nums string字符串 数字串
# @return int整型
#
class Solution:
def solve(self , nums: str) -> int:
# write code here
count=[]
for i in range(len(nums)):
if i==0:
if int(nums[i])>0:
count.append(1)
else:
count.append(0)
elif i==1:
if 0<int(nums[i-1:i+1])<=26 and int(nums[i])!=0:
count.append(2)
else:
count.append(1)
else:
if 10<=int(nums[i-1:i+1])<=26 and int(nums[i])!=0:
count.append(count[i-2]+count[i-1])
elif int(nums[i])==0 and 10<=int(nums[i-1:i+1])<=26:
count.append(count[i-2])
elif int(nums[i])==0 :
return 0
else:
count.append(count[i-1])
return count[-1]
# 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
#
# 解码
# @param nums string字符串 数字串
# @return int整型
#
class Solution:
def solve(self , nums: str) -> int:
# write code here
count=[]
for i in range(len(nums)):
if i==0:
if int(nums[i])>0:
count.append(1)
else:
count.append(0)
elif i==1:
if 0<int(nums[i-1:i+1])<=26 and int(nums[i])!=0:
count.append(2)
else:
count.append(1)
else:
if 10<=int(nums[i-1:i+1])<=26 and int(nums[i])!=0:
count.append(count[i-2]+count[i-1])
elif int(nums[i])==0 and 10<=int(nums[i-1:i+1])<=26:
count.append(count[i-2])
elif int(nums[i])==0 :
return 0
else:
count.append(count[i-1])
return count[-1]