题解 | #字符串加解密#

def cherk(a, b):
    s1 = 'abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789'
    s2 = 'BCDEFGHIJKLMNOPQRSTUVWXYZAbcdefghijklmnopqrstuvwxyza1234567890'
    c = []
    if b == 1:
        for i in a:
            if i in s1:
                c.append(s2[s1.index(i)]) //按照s1中i的索引在s2中取出对应的值，存入c中。
            else:
                c.append(i)  //如果不属于s1,即是特殊字符，不在处理直接存入c中即可；解密和加密逻辑一样
        return ''.join(c)
    if b == 0:
        for i in a:
            if i in s2:
                c.append(s1[s2.index(i)])
            else:
                c.append(i)
        return ''.join(c)


while True:
    try:
        m1 = input()
        m2 = input()
        print(cherk(m1, 1))
        print(cherk(m2, 0))
    except:
        break