题解 | #删除有序链表中重复的元素-I#

#     def __init__(self, x):
#         self.val = x
#         self.next = None
#
# 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
#
# 
# @param head ListNode类 
# @return ListNode类
#
class Solution:
    def deleteDuplicates(self , head: ListNode) -> ListNode:
        # write code here
        if head == None or head.next ==None:
            return head
        Head = head
        pre = head
        nxt = pre.next
        while nxt != None:
            if nxt.val == pre.val:
                pre.next = nxt.next
                nxt = pre.next
            else:
                pre = nxt
                nxt = pre.next
        return Head