题解 | #牛牛学数列2#
牛牛学数列2
http://www.nowcoder.com/practice/fc72951f52984f3abd286d82eeffacba
#include<stdio.h>
int main()
{
int N,i;
double s=0;
scanf("%d",&N);
for(i=1;i<=N;i++){
s=s+(1/(double)i);
}
printf("%.6lf",s);
return 0;
}
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