题解 | #扑克牌大小#

while True:
    try:
        a = input().split('-') #分开为两手牌
        first_poker,second_poker =a[0],a[1]
        type_1 = 0
        type_2 = 0
        first_poker = (first_poker.split()) #按空格将牌分开
        second_poker = (second_poker.split())
        len_1 = len(first_poker)
        len_2 = len(second_poker)
        if(len_1 == 1): #type = 1，2，3，4，5，6分别代表 单牌，对子，三张，炸弹，顺子，对王
            type_1 = 1
        if(len_1 == 2):
            if(first_poker[0] == 'joker'): #两张牌有可能是对子也有可能是对王
                type_1 = 6
            else:
                type_1 = 2
        if(len_1 == 3):
            type_1 = 3
        if(len_1 == 4):
            type_1 = 4
        if(len_1 == 5):
            type_1 = 5
            
        if(len_2 == 1):
            type_2 = 1
        if(len_2 == 2):
            if(second_poker[0] == 'joker'):
                type_2 = 6 
            else:
                type_2 = 2
        if(len_2 == 3):
            type_2 = 3
        if(len_2 == 4):
            type_2 = 4
        if(len_2 == 5):
            type_2 = 5
        S = {'3': 3, '4': 4,'5': 5,'6': 6,'7': 7,'8': 8,'9': 9,'10': 10,'J': 11,'Q': 12,'K': 13,'A': 14,'2': 15,'joker':16,'JOKER':17} #按题目给的表示每张牌的大小顺序赋值
        if(type_1 != type_2): #不是同一类型的
            if(type_1 == 6) | (type_2 == 6):#可能有王炸
                if(type_1 == 6):
                    print('joker JOKER')
                if(type_2 == 6):
                    print('joker JOKER')
            elif(type_1 == 4) | (type_2 == 4): #可能有炸弹
                if(type_1 == 4):
                    print(*first_poker)
                if(type_2 == 4):
                    print(*second_poker)
            else: #不是以上两种情况则认为无法比较
                print('ERROR')
        else: #否则
            if(S[first_poker[0]] > S[second_poker[0]]): #只需要看第一张牌的大小就能比出来整幅牌的大小顺序
                print(*first_poker)
            else:
                print(*second_poker)
    except:
        break