题解 | #坐标移动#
坐标移动
http://www.nowcoder.com/practice/119bcca3befb405fbe58abe9c532eb29
思路分析:存下输入进行切片后遍历判断是否满足条件: wsad开头数字结尾长度2~3位,字典存下其变化最后相加减得出最终位置。
inputs1 = sys.stdin.readline().strip()
list1 = inputs1.split(';')
dict1 = {'W':0,'S':0,'A':0,'D':0}
for i in list1:
if len(i)>3 or len(i)<2 or i[0] not in dict1 or not i[1:].isdigit():
continue
else:
dict1[i[0]] += int(i[1:])
print(str(dict1['D']-dict1['A']) + ',' + str(dict1['W']-dict1['S']))