题解 | #简单计算器#

简单计算器

http://www.nowcoder.com/practice/b8f770674ba7468bb0a0efcc2aa3a239

#include <stdio.h>

int main(void) {
	double num1 = 0.0, num2 = 0.0;//float精度不够
	char ch = '0';
	scanf("%lf %c %lf", &num1, &ch, &num2);
	if (ch == '+' || ch == '-' || ch == '*' || ch == '/') {
		if (ch == '+') {
			printf("%.4lf+%.4lf=%.4lf", num1, num2, num1+num2);
		}
		if (ch == '-') {
			printf("%.4lf-%.4lf=%.4lf", num1, num2, num1-num2);
		}
		if (ch == '*') {
			printf("%.4lf*%.4lf=%.4lf", num1, num2, num1*num2);
		}
		if (ch == '/') {
			if (num2 == 0.0) {
				printf("Wrong!Division by zero!");
			}
			else {
				printf("%.4lf/%.4lf=%.4lf", num1, num2, num1/num2);
			}
		}
	}
	else {
		printf("Invalid operation!");
	}
	return 0;
}
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