JUC-生产者消费者面试题

生产者消费者模式面试题3道

/**
 * 面试题:模拟银行账户
 * 对业务写方法加锁
 * 对业务读方法不加锁
 * 这样行不行?
 * 容易产生脏读问题(dirtyRead)
 */

import java.util.concurrent.TimeUnit;

public class Account {
	String name;
	double balance;
	
	public synchronized void set(String name, double balance) {
		this.name = name;

		try {
			Thread.sleep(2000);
		} catch (InterruptedException e) {
			e.printStackTrace();
		}

		
		this.balance = balance;
	}
	
	public /*synchronized*/ double getBalance(String name) {
		return this.balance;
	}
	
	
	public static void main(String[] args) {
		Account a = new Account();
		new Thread(()->a.set("zhangsan", 100.0)).start();
		
		try {
			TimeUnit.SECONDS.sleep(1);
		} catch (InterruptedException e) {
			e.printStackTrace();
		}
		
		System.out.println(a.getBalance("zhangsan"));
		
		try {
			TimeUnit.SECONDS.sleep(2);
		} catch (InterruptedException e) {
			e.printStackTrace();
		}
		
		System.out.println(a.getBalance("zhangsan"));
	}
}

synchronized方法和非synchronized方法可以同时执行。

看场景,如果业务如果允许脏读,就不用加锁。

面试题

  • 实现一个容器,提供两个方法,add,size
  • 写两个线程,线程1添加10个元素到容器中,线程2实现监控元素的个数,当个数到5个时,线程2给出提示并结束

方法1


import java.util.ArrayList;
import java.util.List;
import java.util.concurrent.TimeUnit;


public class T01_NotifyHoldingLock { //wait notify

	//添加volatile,使t2能够得到通知
	volatile List lists = new ArrayList();

	public void add(Object o) {
		lists.add(o);
	}

	public int size() {
		return lists.size();
	}
	
	public static void main(String[] args) {
		T01_NotifyHoldingLock c = new T01_NotifyHoldingLock();
		
		final Object lock = new Object();
		
		new Thread(() -> {
			synchronized(lock) {
				System.out.println("t2启动");
				if(c.size() != 5) {
					try {
						lock.wait();
					} catch (InterruptedException e) {
						e.printStackTrace();
					}
				}
				System.out.println("t2 结束");
			}
			
		}, "t2").start();
		
		try {
			TimeUnit.SECONDS.sleep(1);
		} catch (InterruptedException e1) {
			e1.printStackTrace();
		}

		new Thread(() -> {
			System.out.println("t1启动");
			synchronized(lock) {
				for(int i=0; i<10; i++) {
					c.add(new Object());
					System.out.println("add " + i);
					
					if(c.size() == 5) {
						//注意注意:nofify不释放锁
						lock.notify();
					}
					
					try {
						TimeUnit.SECONDS.sleep(1);
					} catch (InterruptedException e) {
						e.printStackTrace();
					}
				}
			}
		}, "t1").start();
		
		
	}
}

方法2:

public class T02_NotifyFreeLock {

	//添加volatile,使t2能够得到通知
	volatile List lists = new ArrayList();

	public void add(Object o) {
		lists.add(o);
	}

	public int size() {
		return lists.size();
	}
	
	public static void main(String[] args) {
		T02_NotifyFreeLock c = new T02_NotifyFreeLock();
		
		final Object lock = new Object();
		
		new Thread(() -> {
			synchronized(lock) {
				System.out.println("t2启动");
				if(c.size() != 5) {
					try {
						lock.wait();
					} catch (InterruptedException e) {
						e.printStackTrace();
					}
				}
				System.out.println("t2 结束");
				//通知t1继续执行
				lock.notify();
			}
			
		}, "t2").start();
		
		try {
			TimeUnit.SECONDS.sleep(1);
		} catch (InterruptedException e1) {
			e1.printStackTrace();
		}

		new Thread(() -> {
			System.out.println("t1启动");
			synchronized(lock) {
				for(int i=0; i<10; i++) {
					c.add(new Object());
					System.out.println("add " + i);
					
					if(c.size() == 5) {
						lock.notify();

						//释放锁,让t2得以执行
						try {
							lock.wait(); //wait释放锁
						} catch (InterruptedException e) {
							e.printStackTrace();
						}
					}
					
					try {
						TimeUnit.SECONDS.sleep(1);
					} catch (InterruptedException e) {
						e.printStackTrace();
					}
				}
			}
		}, "t1").start();
	}
}

方法3:

public class T03_CountDownLatch {

	// 添加volatile,使t2能够得到通知
	volatile List lists = new ArrayList();

	public void add(Object o) {
		lists.add(o);
	}

	public int size() {
		return lists.size();
	}

	public static void main(String[] args) {
		T03_CountDownLatch c = new T03_CountDownLatch();

		CountDownLatch latch = new CountDownLatch(1);

		new Thread(() -> {
			System.out.println("t2启动");
			if (c.size() != 5) {
				try {
					latch.await();
					
					//也可以指定等待时间
					//latch.await(5000, TimeUnit.MILLISECONDS);
				} catch (InterruptedException e) {
					e.printStackTrace();
				}
			}
			System.out.println("t2 结束");

		}, "t2").start();

		try {
			TimeUnit.SECONDS.sleep(1);
		} catch (InterruptedException e1) {
			e1.printStackTrace();
		}

		new Thread(() -> {
			System.out.println("t1启动");
			for (int i = 0; i < 10; i++) {
				c.add(new Object());
				System.out.println("add " + i);

				if (c.size() == 5) {
					// 打开门闩,让t2得以执行
					latch.countDown();
				}
			}

		}, "t1").start();

	}
}

方法四:


public class T04_LockSupport {

	// 添加volatile,使t2能够得到通知
	volatile List lists = new ArrayList();

	public void add(Object o) {
		lists.add(o);
	}

	public int size() {
		return lists.size();
	}

	public static void main(String[] args) {
		T04_LockSupport c = new T04_LockSupport();

		CountDownLatch latch = new CountDownLatch(1);

		Thread t2 = new Thread(() -> {
			System.out.println("t2启动");
			if (c.size() != 5) {

				LockSupport.park();

			}
			System.out.println("t2 结束");


		}, "t2");

		t2.start();

		try {
			TimeUnit.SECONDS.sleep(1);
		} catch (InterruptedException e1) {
			e1.printStackTrace();
		}

		new Thread(() -> {
			System.out.println("t1启动");
			for (int i = 0; i < 10; i++) {
				c.add(new Object());
				System.out.println("add " + i);

				if (c.size() == 5) {
					LockSupport.unpark(t2);
				}

				/*try {
					TimeUnit.SECONDS.sleep(1);
				} catch (InterruptedException e) {
					e.printStackTrace();
				}*/
			}

		}, "t1").start();

	}
}

方法五:

public class T05_LockSupport_WithoutSleep {

	// 添加volatile,使t2能够得到通知
	volatile List lists = new ArrayList();

	public void add(Object o) {
		lists.add(o);
	}

	public int size() {
		return lists.size();
	}

	static Thread t1 = null, t2 = null;

	public static void main(String[] args) {
		T05_LockSupport_WithoutSleep c = new T05_LockSupport_WithoutSleep();

		t1 = new Thread(() -> {
			System.out.println("t1启动");
			for (int i = 0; i < 10; i++) {
				c.add(new Object());
				System.out.println("add " + i);

				if (c.size() == 5) {
					LockSupport.unpark(t2);
					LockSupport.park();
				}
			}
		}, "t1");

		t2 = new Thread(() -> {
			//System.out.println("t2启动");
			//if (c.size() != 5) {
				LockSupport.park();
			//}
			System.out.println("t2 结束");
			LockSupport.unpark(t1);
		}, "t2");
		t2.start();
		t1.start();
	}
}

方法六:

public class T06_Semaphore {
    // 添加volatile,使t2能够得到通知
    volatile List lists = new ArrayList();

    public void add(Object o) {
        lists.add(o);
    }

    public int size() {
        return lists.size();
    }

    static Thread t1 = null, t2 = null;

    public static void main(String[] args) {
        T06_Semaphore c = new T06_Semaphore();
        Semaphore s = new Semaphore(1);

        t1 = new Thread(() -> {
            try {
                s.acquire();
                for (int i = 0; i < 5; i++) {
                    c.add(new Object());
                    System.out.println("add " + i);


                }
                s.release();
            } catch (InterruptedException e) {
                e.printStackTrace();
            }

            try {
                t2.start();
                t2.join();
            } catch (InterruptedException e) {
                e.printStackTrace();
            }

            try {
                s.acquire();
                for (int i = 5; i < 10; i++) {
                    System.out.println(i);
                }
                s.release();
            } catch (InterruptedException e) {
                e.printStackTrace();
            }

        }, "t1");

        t2 = new Thread(() -> {
            try {
                s.acquire();
                System.out.println("t2 结束");
                s.release();
            } catch (InterruptedException e) {
                e.printStackTrace();
            }
        }, "t2");

        //t2.start();
        t1.start();
    }
}

面试题:写一个固定容量同步容器,拥有put和get方法,以及getCount方法, 能够支持2个生产者线程以及10个消费者线程的阻塞调用

wait和notify/notifyAll来实现

public class MyContainer1<T> {
	final private LinkedList<T> lists = new LinkedList<>();
	final private int MAX = 10; //最多10个元素
	private int count = 0;
	
	
	public synchronized void put(T t) {
		while(lists.size() == MAX) { //为什么用while而不是用if?
			try {
				this.wait(); //effective java 中
			} catch (InterruptedException e) {
				e.printStackTrace();
			}
		}
		
		lists.add(t);
		++count;
		this.notifyAll(); //通知消费者线程进行消费
	}
	
	public synchronized T get() {
		T t = null;
		while(lists.size() == 0) {
			try {
				this.wait();
			} catch (InterruptedException e) {
				e.printStackTrace();
			}
		}
		t = lists.removeFirst();
		count --;
		this.notifyAll(); //通知生产者进行生产
		return t;
	}
	
	public static void main(String[] args) {
		MyContainer1<String> c = new MyContainer1<>();
		//启动消费者线程
		for(int i=0; i<10; i++) {
			new Thread(()->{
				for(int j=0; j<5; j++) System.out.println(c.get());
			}, "c" + i).start();
		}
		
		try {
			TimeUnit.SECONDS.sleep(2);
		} catch (InterruptedException e) {
			e.printStackTrace();
		}
		
		//启动生产者线程
		for(int i=0; i<2; i++) {
			new Thread(()->{
				for(int j=0; j<25; j++) c.put(Thread.currentThread().getName() + " " + j);
			}, "p" + i).start();
		}
	}
}

使用Lock和Condition来实现 对比两种方式,Condition的方式可以更加精确的指定哪些线程被唤醒

import java.util.LinkedList;
import java.util.concurrent.TimeUnit;
import java.util.concurrent.locks.Condition;
import java.util.concurrent.locks.Lock;
import java.util.concurrent.locks.ReentrantLock;

public class MyContainer2<T> {
	final private LinkedList<T> lists = new LinkedList<>();
	final private int MAX = 10; //最多10个元素
	private int count = 0;
	
	private Lock lock = new ReentrantLock();
	//condition 本质是等待队列的个数
	private Condition producer = lock.newCondition();
	private Condition consumer = lock.newCondition();
	
	public void put(T t) {
		try {
			lock.lock();
			while(lists.size() == MAX) { //为什么用while而不是用if?
				producer.await();
			}
			
			lists.add(t);
			++count;
			consumer.signalAll(); //通知消费者线程进行消费
		} catch (InterruptedException e) {
			e.printStackTrace();
		} finally {
			lock.unlock();
		}
	}
	
	public T get() {
		T t = null;
		try {
			lock.lock();
			while(lists.size() == 0) {
				consumer.await();
			}
			t = lists.removeFirst();
			count --;
			producer.signalAll(); //通知生产者进行生产
		} catch (InterruptedException e) {
			e.printStackTrace();
		} finally {
			lock.unlock();
		}
		return t;
	}
	
	public static void main(String[] args) {
		MyContainer2<String> c = new MyContainer2<>();
		//启动消费者线程
		for(int i=0; i<10; i++) {
			new Thread(()->{
				for(int j=0; j<5; j++) System.out.println(c.get());
			}, "c" + i).start();
		}
		
		try {
			TimeUnit.SECONDS.sleep(2);
		} catch (InterruptedException e) {
			e.printStackTrace();
		}
		
		//启动生产者线程
		for(int i=0; i<2; i++) {
			new Thread(()->{
				for(int j=0; j<25; j++) c.put(Thread.currentThread().getName() + " " + j);
			}, "p" + i).start();
		}
	}
}

面试题:要求用两个线程交替打印A1B2C3D4......

public class T02_00_LockSupport {


    static Thread t1 = null, t2 = null;

    public static void main(String[] args) throws Exception {
        char[] aI = "1234567".toCharArray();
        char[] aC = "ABCDEFG".toCharArray();

        t1 = new Thread(() -> {

                for(char c : aI) {
                    System.out.print(c);
                    LockSupport.unpark(t2); //叫醒T2
                    LockSupport.park(); //T1阻塞
                }

        }, "t1");

        t2 = new Thread(() -> {

            for(char c : aC) {
                LockSupport.park(); //t2阻塞
                System.out.print(c);
                LockSupport.unpark(t1); //叫醒t1
            }

        }, "t2");

        t1.start();
        t2.start();
    }
}
public class T03_00_cas {

    enum ReadyToRun {T1, T2}

    static volatile ReadyToRun r = ReadyToRun.T1; //思考为什么必须volatile

    public static void main(String[] args) {

        char[] aI = "1234567".toCharArray();
        char[] aC = "ABCDEFG".toCharArray();

        new Thread(() -> {

            for (char c : aI) {
                while (r != ReadyToRun.T1) {}
                System.out.print(c);
                r = ReadyToRun.T2;
            }

        }, "t1").start();

        new Thread(() -> {

            for (char c : aC) {
                while (r != ReadyToRun.T2) {}
                System.out.print(c);
                r = ReadyToRun.T1;
            }
        }, "t2").start();
    }
}
public class T04_00_BlockingQueue {


    static BlockingQueue<String> q1 = new ArrayBlockingQueue(1);
    static BlockingQueue<String> q2 = new ArrayBlockingQueue(1);

    public static void main(String[] args) throws Exception {
        char[] aI = "1234567".toCharArray();
        char[] aC = "ABCDEFG".toCharArray();

        new Thread(() -> {

            for(char c : aI) {
                System.out.print(c);
                try {
                    q1.put("ok");
                    q2.take();
                } catch (InterruptedException e) {
                    e.printStackTrace();
                }
            }

        }, "t1").start();

        new Thread(() -> {

            for(char c : aC) {
                try {
                    q1.take();
                } catch (InterruptedException e) {
                    e.printStackTrace();
                }
                System.out.print(c);
                try {
                    q2.put("ok");
                } catch (InterruptedException e) {
                    e.printStackTrace();
                }
            }

        }, "t2").start();


    }
}
public class T05_00_AtomicInteger {

    static AtomicInteger threadNo = new AtomicInteger(1);


    public static void main(String[] args) {

        char[] aI = "1234567".toCharArray();
        char[] aC = "ABCDEFG".toCharArray();


        new Thread(() -> {

            for (char c : aI) {
                while (threadNo.get() != 1) {}
                System.out.print(c);
                threadNo.set(2);
            }

        }, "t1").start();

        new Thread(() -> {

            for (char c : aC) {
                while (threadNo.get() != 2) {}
                System.out.print(c);
                threadNo.set(1);
            }
        }, "t2").start();
    }
}

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迷qwq:比我本科强多了,找个不错的工作问题不大,更好的工作就得看面试表现加上运气了。另外自身经历不错,简历写的不太好,再润色一下。
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