题解 | #人民币转换#

while 1:
    try:
        s=input()
        q,h=s.strip().split('.')[0],s.strip().split('.')[1]
        n=float(s)
        d={'0':'零','1':'壹','2':'贰','3':'叁','4':'肆','5':'伍','6':'陆','7':'柒','8':'捌','9':'玖'}
        d2={0:'',1:'拾',2:'佰',3:'仟',4:'万',5:'亿'}
        s='人民币'
        if q !='0':
            ql=list(q)
            l=[]
            while len(ql)>=4:
                l.append(''.join(ql[-4::]))
                for _ in range(4):
                    ql.pop()
            if ql:
                l.append(''.join(ql[::]))
#             print(l)
            sl=[]
            for i in range(len(l)):
                ss=''
                le=len(l[i])
                c=1
                for j in range(le):
                    if l[i][j]!='0':
                        if l[i][j]=='1' and le-j-1==1:
                            ss+=d2[le-j-1]
                        else:
                            ss+=(d[l[i][j]]+d2[le-j-1])
                        c=1
                    elif l[i][j]=='0' and c:
                        ss+=d[l[i][j]]
                        c=0
                if i>=1:
                    ss+=d2[i+3]
                sl.append(ss)
            sl.reverse()
            s+=(''.join(sl)+'元').replace('拾零','拾').replace('仟零元','仟元')
        if h=='00':
            s+='整'
        elif h !='00':
            if h[0]!='0':
                s+=d[h[0]]+'角'
            if h[1]!='0':
                s+=d[h[1]]+'分'
        print(s)
    except:
        break