题解 | #时间转换#
时间转换
http://www.nowcoder.com/practice/c4ae7bcac7f9491b8be82ee516a94899
#include <stdio.h>
int main()
{
int second;
scanf("%d", &second);
printf("%d %d %d", second / 3600, (second % 3600) / 60, (second % 3600) % 60);
return 0;
}
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