题解 | #获得积分最多的人(二)#
获得积分最多的人(二)
http://www.nowcoder.com/practice/b6248d075d2d4213948b2e768080dc92
with total as(
select a.id,name,sum(grade_num) over(partition by name)as grade_sum
from user a
left join grade_info b
on a.id=b.user_id
order by grade_sum desc
)
select id,name,grade_sum
from total
where grade_sum in(
select max(grade_sum)
from total
)
group by id
order by id 
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