题解 | #获得积分最多的人(二)#

from汇总个人积分
where找出最高积分
select DISTINCT id, name, grade_sum
FROM (select DISTINCT u.id, u.name, sum(g.grade_num) as grade_sum
FROM user as u right join grade_info as g
on u.id = g.user_id
group by g.user_id
order by grade_sum desc
) as dd
where grade_sum = (select sum(g.grade_num) as grade_sum
FROM user as u right join grade_info as g
on u.id = g.user_id
group by g.user_id
order by grade_sum desc
LIMIT 1)
;