题解 | #反转链表#
反转链表
http://www.nowcoder.com/practice/75e878df47f24fdc9dc3e400ec6058ca
原链表不断取头，新链表头插
class Solution {
public:
ListNode* ReverseList(ListNode* pHead) {
ListNode* newHead = nullptr;
while(pHead){
//原链表取头
ListNode* tmp = pHead;
pHead = pHead->next;
//新链表头插
tmp->next = newHead;
newHead = tmp;
}
return newHead;
}
};
