python3 直观处理
查找兄弟单词
http://www.nowcoder.com/questionTerminal/03ba8aeeef73400ca7a37a5f3370fe68
while True: try: s_list = input().split() num, k = int(s_list[0]), int(s_list[-1]) words = s_list[1: 1+num] find_word = s_list[-2] res = [] for i in words: if sorted(i) == sorted(find_word) and i != find_word: res.append(i) print(len(res)) # 最后的判断 k if res&nbs***bsp;k <= len(res): print(sorted(res)[k-1]) except: break
投递快手等公司10个岗位
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