NC20272 [SCOI2009]生日快乐(DFS)
[SCOI2009]生日快乐
https://ac.nowcoder.com/acm/problem/20272
题意:
题解:
AC代码
/*
Author : zzugzx
Lang : C++
Blog : blog.csdn.net/qq_43756519
*/
#include<bits/stdc++.h>
using namespace std;
#define fi first
#define se second
#define pb push_back
#define mp make_pair
#define all(x) (x).begin(), (x).end()
#define endl '\n'
#define SZ(x) (int)x.size()
typedef long long ll;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;
const int mod = 1e9+7;
//const int mod = 998244353;
const double eps = 1e-10;
const double pi = acos(-1.0);
const int maxn = 1e6+10;
const ll inf = 0x3f3f3f3f;
const int dir[][2]={{0, 1}, {1, 0}, {0, -1}, {-1, 0}, {1, 1}, {1, -1}, {-1, 1}, {-1, -1}};
double dfs(double x, double y, int n) {
if (n == 1)
return max(x, y) / min(x, y);
double a = x / n, b = y / n, ans = inf;
for (int i = 1; i <= n / 2; i++)
ans = min(ans, min(max(dfs(i * a, y, i), dfs(x - i * a, y, n - i)), max(dfs(x, i * b, i), dfs(x, y - i * b, n - i))));
return ans;
}
int main()
{
int x, y, n;
scanf("%d%d%d", &x, &y, &n);
printf("%.6f\n", dfs(x, y, n));
return 0;
}
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