序列交换
序列交换
http://www.nowcoder.com/questionTerminal/2d2d27effda849968aaab26f37b83c52
def solve(nums):
if len(nums) == 0:
return []
odd = 0 # 数组中偶数的个数
for i in range(len(nums)):
if nums[i] % 2 == 0:
odd += 1
if odd == 0 or odd == len(nums): # 数组全为偶数或者全为奇数
return nums # 不能变换位置
else: return sorted(nums) # 进行排序即可
n = int(input())
nums = list(map(int,input().split()))
res = solve(nums)
for i in range(n):
print(res[i],end = ' ')
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