//1022 D进制的A+B (20分) P94
//1022 D进制的A+B (20分) P94
#include <iostream>
#define maxSize 100
using namespace std;
int main(){
unsigned int A,B,C,D,result[maxSize] ={};
while(cin>>A>>B>>D){
C = A+B;
int n=0;
do{
result[n] = C%D;
C /= D;
++n;
}while(C>0);
for(int i=n-1;i>=0;--i) cout<<result[i];
cout<<endl;
}
return 0;
}