简单密码 python3的粗暴解法
简单密码
http://www.nowcoder.com/questionTerminal/7960b5038a2142a18e27e4c733855dac
while True:
try:
s = input()
res = []
for i in s:
if i.isdigit():
res.append(i)
elif i.isupper() and i != 'Z':
res.append(chr(ord(i.lower()) + 1))
elif i == 'Z':
res.append('a')
else:
if i in 'abc':
res.append('2')
elif i in 'def':
res.append('3')
elif i in 'ghi':
res.append('4')
elif i in 'jkl':
res.append('5')
elif i in 'mno':
res.append('6')
elif i in 'pqrs':
res.append('7')
elif i in 'tuv':
res.append('8')
else:
res.append('9')
print(''.join(res))
except:
break
简单粗暴没什么好讲的