WITH t1 AS ( -- 关联两表清洗数据,并计算出每个员工上半年的绩效总分 SELECT yg.employee_id, yg.employee_name, yg.department, xm.project_name AS project_group, jx.project_id, ROUND(COALESCE(SUM(jx.performance_score),0),0) AS first_half_2024_score FROM employees AS yg LEFT JOIN performance AS jx ON yg.employee_id = jx.employee_...