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想要上岸的水鬼:取连续出现3次的数字,可考虑:
select
distinct
NUM
from
(
select
NUM,
rn_Id - rn_NUM as rn_ID_gp,
count(1) as cnt
from
(
select
NUM,
row_number() over(order by Id) as rn_Id,
row_number() over(partition by NUM order by Id) as rn_NUM
from
NUM_table
) a
group by
NUM,
rn_Id - rn_NUM
) t
where
cnt >= 3

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求个offer!~:请问是没有HR面,二面出结果直接通知是吗?

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创作者周榜
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