#include <stdio.h> void max(int a,int b,int c) { int n1=b>c?b:c; int n2=a>c?a:c; int n3=a>b?a:b; int max1=n1>(a+b)?n1:(a+b); int max2=n2>(b+c)?n2:(b+c); int max3=n3>(b+c)?n3:(b+c); float m=1.0*max1/(max2+max3); printf("%.2f",m); ...