题解 | #小乐乐计算函数#

#include <stdio.h>

void max(int a,int b,int c)
{
    int n1=b>c?b:c;
    int n2=a>c?a:c;
    int n3=a>b?a:b;

    int max1=n1>(a+b)?n1:(a+b);
    int max2=n2>(b+c)?n2:(b+c);
    int max3=n3>(b+c)?n3:(b+c);

    float m=1.0*max1/(max2+max3);
    printf("%.2f",m);
    
}

int main() 
{
    int a=0,b=0,c=0;
    scanf("%d %d %d",&a,&b,&c);
    max(a,b,c);  
    return 0;
}