美团0817笔试第三题a

事后回忆的解法，应该没错叭。(*￣m￣)。不过第二题题目啥意思呀，求个路过的好心人解惑一下。

l=[2,2,3,4,5,6,7]
avg=sum(l)/len(l)
avg
count=0
if avg-int(avg)==0: # l=[1,2,3,4,5] 3.0做差即可
    for i in l:
        if avg-i>=1:
            count+=int(avg)-i
    print(count)
else:
    down_=int(avg)
    up_=int(avg)+1
    count_d=0
    count_u=0
    for i in l:
        if iup_:
            count_u+=i-up_
    # (5,3)次选5次,因为[4,4,4,4,5,5,5]后还需要进行加1次（5-3）=2次，2次可以被容纳，最后变为 [4,4,5,5,5,5,5]
    print(max(count_d,count_u))