恒生交付工程师笔试(C++)
单选题7道,多选题7道,填空题 1道,编程题3道
编程题1:小C的完全平方2
编程题2:农业监控系统(sql)
编程题3:坏掉的机器
编程题1:小C的完全平方2
编程题2:农业监控系统(sql)
编程题3:坏掉的机器
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10-10 20:27
西安工业大学 运维开发工程师
牛6666666__:select f.farm_name as farm_name,
c.crop_name,
c.crop_type,
round(avg(health_index), 2) as avg_health_index,
round(sum(yield_kg_per_hectare),0) as avg_yield_kg_per_hectare,
datediff(max(measurement_date), min(planting_date)) as growth_days
from crop_data cd
inner join farms f on cd.farm_id = f.farm_id
inner join crops c on cd.crop_id = c.crop_id
where cd.measurement_date between '2024-03-01' and '2024-06-30'
group by cd.crop_id, cd.farm_id,f.farm_name
having count(cd.data_id) >= 3
order by avg_health_index desc, avg_yield_kg_per_hectare desc,farm_name 点赞 评论 收藏
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