import java.util.Scanner; ////思路：找到1和1之间的0的个数n,判断(n-2)/2是奇数还是偶数[前提是n-2>0] //如果是奇数则（n-2）/2+1,偶数则(n-2)/2 public class xiaomi1 {           static boolean fun(String table, int n) {         int i=0;         boolean flag = true ; //true:1 false:0         int count = 0 ;         if(table.charAt(i)=='1'){             flag = true ;         }else if(table.charAt(i)=='0'){             count++;             flag=false;         }         i++;         int mm=0;         while(i<table.length())         {             if(flag){                 if(table.charAt(i)=='0'){                     if(count-2>0 && (count-2)%2 == 0){                         mm=mm+(count-2)/2 ;                     }else if(count-2>0 && (count-2)%2 != 0){                         mm=mm+(count-2)/2 +1;                     }                     count=1;                     flag=false;                 }else{                     count=0;                     flag=true;                 }             }else{                 if(table.charAt(i)=='0'){                     count++;                     flag=false;                 }else{                     if(count-2>0 && (count-2)%2 == 0){                         mm=mm+(count-2)/2 ;                     }else if(count-2>0 && (count-2)%2 != 0){                         mm=mm+(count-2)/2 +1;                     }                     count=0;                     flag=true;                 }             }             i++;                      }         //System.out.println(mm);         //System.out.println(n);         return mm>=n?true:false ;     }          public static void main(String[] args) {         Scanner in = new Scanner(System.in);         boolean res;                      String _table;         try {             _table = in.nextLine();         } catch (Exception e) {             _table = null;         }                  int _n;         _n = Integer.parseInt(in.nextLine().trim());            //res = fun(_table, _n);         System.out.println(fun(_table, _n));                } }