第二题 #include<stdio.h> #include<string> #include<iostream> using namespace std; int main() {     int n;     cin >> n;     int a[10000];     int b[10000];     for (int i = 0; i < n + 1; i++)          cin >> a[i];     for (int i = 0; i < n; i++)          cin >> b[i];     /*以上是输入接收*/     int sum = 0;     for (int i = 0; i < n; i++) {         if (a[i] + a[i + 1] >= b[i]) {             sum += b[i];             if (a[i] <= b[i])                 a[i + 1] = a[i] + a[i + 1] - b[i];         }         else {             sum += a[i] + a[i + 1];             a[i + 1] = 0;         }     }     cout << sum << endl;    // system("pause"); }