求大佬帮我看下:select date_format(submit_time,'%Y%m') as month, round(count(distinct uid,date_format(submit_time,'%Y%m%d')) / count(distinct uid),2) avg_active_days, count(distinct uid) mau from exam_record where submit_time is not null and year(submit_time)=2001 group by date_format(submit_time,'%Y%m')。跟正确答案了好几遍,到底哪里错了?
点赞

相关推荐

牛客网
牛客网在线编程
牛客网题解
牛客企业服务