题解 | 手机键盘

def solution(s):
    keys = "22233344455566677778889999"
    # 每个字母在键上的位置（第几次按键）
    press = [1, 2, 3, 1, 2, 3, 1, 2, 3, 1, 2, 3, 1, 2, 3,
             1, 2, 3, 4, 1, 2, 3, 1, 2, 3, 4]
    total = 0
    prev_key = ''
    for ch in s:
        idx = ord(ch) - ord('a')
        cur_key = keys[idx]
        total += press[idx]
        if cur_key == prev_key:
            total += 2
        prev_key = cur_key
    return total
while True:
    try:
        s = input()
        print(solution(s))
    except :
        break