题解 | 构造数独
构造数独
https://www.nowcoder.com/practice/bf8ffcbf95f743d7bbb2dd96bafa1a3c
#include <iostream>
using namespace std;
int a[1005][1005];
int main(){
int n,k;
cin>>n>>k;
for(int i=1;i<=n;i++){
for(int j=1;j<=n;j++){
if(i==j){
cout<<k<<' ';
}
else{
cout<<a[i][j]<<' ';
}
}
cout<<endl;
}
return 0;
}
