题解 | #智乃的箭头魔术#
智乃的二进制
https://ac.nowcoder.com/acm/contest/120565/A
代码演示:
#include<bits/stdc++.h>
using namespace std;
#define int long long
#define endl '\n'
const int N = 500010;
void solve(){
int f=0;
string s="0112233445142015320125410214530214510214102302142025101203201451451522302514203214510021454101002532";
for(int i=0;i<s.length();i++){
if(s[i]=='0'){
f=3-f;
}else if(s[i]=='1'){
if(f%2==1){
f=4-f;
}
}else if(s[i]=='2'){
f=f^1;
}else if(s[i]=='3'){
if(f==0) f=2;
else if(f==2) f=0;
}else if(s[i]=='4'){
f=(f+1)%4;
}else{
f=(f+3)%4;
}
cout<<f;
}
}
signed main(){
ios::sync_with_stdio(false);cin.tie(0),cout.tie(0);
int T=1;//cin>>T;
while(T--){
solve();
}
return 0;
}
