题解 | 获得积分最多的人(二)
获得积分最多的人(二)
https://www.nowcoder.com/practice/b6248d075d2d4213948b2e768080dc92
with t1 as (
select u.id,u.name,sum(g.grade_num) over(partition by g.user_id) grade_num
from user u
join grade_info g on u.id = g.user_id
)
select distinct id,name,grade_num
from t1
where grade_num = (select max(grade_num) from t1)
order by id
