题解 | 进制转换
进制转换
https://www.nowcoder.com/practice/8f3df50d2b9043208c5eed283d1d4da6
s = input().strip()
hex_part = s[2:]
ans = 0
for ch in hex_part: #for可遍历字符串
ans *= 16
if '0' <= ch <= '9':
ans += ord(ch) - ord('0')
else:
ans += ord(ch) - ord('A') + 10
print(ans)
