题解 | 有序序列合并
有序序列合并
https://www.nowcoder.com/practice/a9e943b0dab142759807d0cfb6863897
#include <stdio.h>
#include <string.h>
int main()
{
int n = 0;
int m = 0;
scanf ("%d %d", &n, &m);
int arr1[n];
int arr2[m];
int arr3[n+m];
int i = 0;
int j = 0;
for (i = 0; i < n; i++)
scanf("%d", &arr1[i]);
for (i = 0; i < m; i++)
scanf("%d", &arr2[i]);
for (i = 0; i < n; i++)
arr3[i] = arr1[i];
for (i = n; i < m + n -1, j < m; i++, j++)
arr3[i] = arr2[j];
for (i = 0; i < m + n; i++)
{
for (j = 0; j < m + n - 1 - i; j++)
{
if (arr3[j] > arr3[j + 1])
{
int temp = 0;
temp = arr3[j];
arr3[j] = arr3[j + 1];
arr3[j + 1] = temp;
}
}
}
//循环输出arr
for (i = 0; i < m + n; i++)
{
printf("%d ", arr3[i]);
}
return 0;
}

查看9道真题和解析