题解 | 时间转换
时间转换
https://www.nowcoder.com/practice/c4ae7bcac7f9491b8be82ee516a94899
#include<bits/stdc++.h>
using namespace std;
int main()
{
int n;
cin>>n;
int a,b,c;
a=n/3600;
b=n%3600/60;
c=n%3600%60;
cout<<a<<" "<<b<<" "<<c;
return 0;
}
