题解 | 买卖股票的最好时机(一)
买卖股票的最好时机(一)
https://www.nowcoder.com/practice/64b4262d4e6d4f6181cd45446a5821ec
#
# 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
#
#
# @param prices int整型一维数组
# @return int整型
#
class Solution:
def maxProfit(self , prices: List[int]) -> int:
# write code here
if not prices or len(prices) == 0 or len(prices) == 1:
return 0
lens = len(prices)
dp = [0]*lens
dp[1] = max(prices[1]-prices[0],0)
for i in range(2,lens):
dp[i] = max(dp[i-1],prices[i]-min(prices[0:i]))
print(dp)
return dp[lens-1]

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