题解 | 凯撒加密
凯撒加密
https://www.nowcoder.com/practice/006b7917d3784371a43cfbae01a9313d
n = int(input())
s = str(input())
mima = []
for i in range(len(s)):
mima.append(chr((ord(s[i]) - ord('a') + n) % 26 + ord('a'))) #超过z
print(''.join(mima)) #转为字符串输出
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