题解 | 输出提交且通过次数大于2 的用户ID且升序排列
输出提交且通过次数大于2 的用户ID且升序排列
https://www.nowcoder.com/practice/180ddfdf30ce4303bac02f4ca0af43d5
select user_id
from
(
select user_id,
sum(
case when result_info =1 then 1
else 0
end
)as cnt
from done_questions_record
group by 1
) b
where cnt > 2
