题解 | N个数之和
N个数之和
https://www.nowcoder.com/practice/b007744eb43b4f7b95d9e87de01528db
#include <stdio.h>
int main() {
int N;
scanf("%d",&N);
int num[N-1];
int total = 0;
for(int i = 0;i<N;i++){
scanf("%d",&num[i]);
}
for(int i = 0;i<N;i++){
total += num[i];
}
printf("%d",total);
return 0;
}