题解 | 牛牛学数列5
牛牛学数列5
https://www.nowcoder.com/practice/6db6674518a9456198c166bcd0d2aaa1
#include <stdio.h>
int main() {
int n;
scanf("%d",&n);
if(n<3)
printf("1");
else
{
int a[n+1];
a[1]=1;
a[2]=1;
for(int i=3;i<=n;i++)
{
a[i]=a[i-1]+a[i-2];
}
printf("%d",a[n]);
}
return 0;
}
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