题解 | 滑动窗口的最大值

#include <queue>
class Solution {
  public:
    vector<int> maxInWindows(vector<int>& num, int size) {
        vector<int>ans = {};
        if (size > num.size() || size == 0) return ans;
        int left = 0;
        for (; left < num.size()-size+1; left++) {
            priority_queue<int, vector<int>> minheap(num.begin()+left, num.begin()+left+size);
            ans.push_back(minheap.top());
        }
        return ans;
    }
};