题解 | 牛牛的计划
牛牛的计划
https://www.nowcoder.com/practice/cf956ceef9f84f7393a0b7284fdbf95a
#include <stdio.h>
int main() {
int y,m,d;
scanf("%d %d %d\n",&y,&m,&d);
int y1,m1,d1;
scanf("%d %d %d",&y1,&m1,&d1);
if (y1>y){
printf ("yes");
}else if (y1==y) {
if (m1>m) {
printf ("yes");
}else if(m1==m){
if(d1>=d){
printf("yes");
}else{printf("no");}
}else {printf("no");}
}else{printf("no");}
return 0;
}
