题解 | 牛牛学数列2
牛牛学数列2
https://www.nowcoder.com/practice/fc72951f52984f3abd286d82eeffacba
#include <stdio.h>
int main() {
int n;
double sum = 0;
scanf("%d", &n);
for (int i = 1; i <= n; i++){
sum += (1.0 / i);
}
printf("%lf", sum);
return 0;
}
，接着当手孝子