题解 | 二叉树的镜像
二叉树的镜像
https://www.nowcoder.com/practice/a9d0ecbacef9410ca97463e4a5c83be7
# class TreeNode: # def __init__(self, x): # self.val = x # self.left = None # self.right = None # # 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可 # # # @param pRoot TreeNode类 # @return TreeNode类 # class Solution: def Mirror(self , pRoot: TreeNode) -> TreeNode: # write code here if pRoot: pRoot.left = self.Mirror(pRoot.left) pRoot.right = self.Mirror(pRoot.right) l_node, r_node = pRoot.left, pRoot.right pRoot.left = r_node pRoot.right = l_node return pRoot